A rope by which a calf is tied is increased f | vedclass

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(C) The area grazed by the calf is the area of a circle with the rope length as the radius.Initial radius $(r_1)$ = $12 \ m$.Final radius $(r_2)$ = $2

Vedclass · Accepted Answer

$1210$

Vedclass · Answer

(C) The area grazed by the calf is the area of a circle with the rope length as the radius.Initial radius $(r_1)$ = $12 \ m$.Final radius $(r_2)$ = $23 \ m$.Additional area grazed = Area with radius $r_2$ - Area with radius $r_1$.Additional area = $\pi r_2^2 - \pi r_1^2 = \pi(r_2^2 - r_1^2)$.Using the identity $a^2 - b^2 = (a - b)(a + b)$:Additional area = $\pi(23 - 12)(23 + 12) = \pi(11)(35)$.Taking $\pi = \frac{22}{7}$:Additional area = $\frac{22}{7} 	imes 11 	imes 35 = 22 	imes 11 	imes 5 = 1210 \ m^2$.

$A$ rope by which a calf is tied is increased from $12 \ m$ to $23 \ m$. How much additional grassy ground shall it graze? (in $m^2$)

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