A self-fertilizing trihybrid plant forms: | vedclass

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(C) For a plant with $n$ heterozygous gene pairs (trihybrid means $n = 3$):$1$. The number of different types of gametes produced is given by the form

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$8$ different gametes and $64$ different zygotes

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(C) For a plant with $n$ heterozygous gene pairs (trihybrid means $n = 3$):$1$. The number of different types of gametes produced is given by the formula $2^n$. For a trihybrid,this is $2^3 = 8$ different gametes.$2$. The number of different types of zygotes (genotypes) produced upon self-fertilization is given by the formula $3^n$. For a trihybrid,this is $3^3 = 27$ genotypes. However,in the context of phenotypic combinations or specific genetic outcomes often tested in this format,the total number of possible combinations in a Punnett square is $4^n$. For a trihybrid,this is $4^3 = 64$ different zygotic combinations.$3$. Therefore,the plant forms $8$ different gametes and $64$ different zygotic combinations.

$A$ self-fertilizing trihybrid plant forms:

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