In a dihybrid cross,considering the character | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) In a dihybrid cross,the $F_1$ generation is heterozygous for two traits (e.g.,$RrYy$).According to the law of independent assortment,the number of

Vedclass · Accepted Answer

Four

Vedclass · Answer

(D) In a dihybrid cross,the $F_1$ generation is heterozygous for two traits (e.g.,$RrYy$).According to the law of independent assortment,the number of types of gametes produced by an organism is calculated by the formula $2^n$,where $n$ is the number of heterozygous gene pairs.Here,$n = 2$ (since the genotype is $RrYy$).Therefore,the number of types of gametes = $2^2 = 4$.The four types of gametes produced are $RY, Ry, rY,$ and $ry$.

In a dihybrid cross,considering the characteristics of the $F_1$ generation obtained from the parental generation and the $F_2$ generation,how many types of gametes (pollen grains) will be produced by the $F_1$ generation?

Similar Questions

In a dihybrid cross,out of $16$ plants obtained in the $F_2$ generation,the number of distinct genotypes is:

$A$ self-fertilizing trihybrid plant forms:

When a cross is made between $Ttrr$ and $Rrtt$, the phenotypic ratio of their progeny will be:

In a dihybrid cross,what is the proportion of $RrYy$ offspring obtained from the selfing of an $RrYy$ plant (in $/16$)?

How many types of gametes will be produced by an individual having genotype $AaBbcc$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module