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(A) The pressure difference across the curved surface of the water in the hole is given by the excess pressure formula for a spherical meniscus,which

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$r = \frac{2T}{hdg}$

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(A) The pressure difference across the curved surface of the water in the hole is given by the excess pressure formula for a spherical meniscus,which is $\Delta P = \frac{2T}{r}$.At equilibrium,this excess pressure must balance the hydrostatic pressure exerted by the water column of height $h$,which is given by $P = hdg$.Equating the two,we get $\frac{2T}{r} = hdg$.Rearranging for $r$,we find $r = \frac{2T}{hdg}$.

$A$ shell having a hole of radius $r$ is dipped in water. It holds the water up to a depth of $h$. Then the value of $r$ is:

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