A shopkeeper has one spherical laddoo of radi | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The volume of a sphere is given by the formula $V = \frac{4}{3} \pi r^3$.Let the radius of the large laddoo be $R = 5 \, cm$ and the radius of the

Vedclass · Accepted Answer

$8$

Vedclass · Answer

(C) The volume of a sphere is given by the formula $V = \frac{4}{3} \pi r^3$.Let the radius of the large laddoo be $R = 5 \, cm$ and the radius of the smaller laddoos be $r = 2.5 \, cm$.Since the total amount of material remains the same,the total volume of the smaller laddoos must equal the volume of the large laddoo.Let $n$ be the number of smaller laddoos.$n 	imes (\frac{4}{3} \pi r^3) = \frac{4}{3} \pi R^3$$n = \frac{R^3}{r^3} = (\frac{R}{r})^3$$n = (\frac{5}{2.5})^3 = (2)^3 = 8$.Therefore,$8$ laddoos of radius $2.5 \, cm$ can be made.

$A$ shopkeeper has one spherical laddoo of radius $5 \, cm$. With the same amount of material,how many laddoos of radius $2.5 \, cm$ can be made?

Similar Questions

Write True or False and justify your answer.
$A$ right circular cylinder just encloses a sphere of radius $r$ as shown in the figure. The surface area of the sphere is equal to the curved surface area of the cylinder.

Find the curved surface area,total surface area and volume of a hemisphere of diameter $42\, cm$.

The radius and height of a cylindrical coin are $1.4 \, cm$ and $0.1 \, cm$ respectively. $60$ such coins are stacked up to make a larger cylindrical pillar. Find the volume of this larger cylinder (in $cm^3$).

Two solid spheres made of the same metal have weights $5920 \, g$ and $740 \, g$ respectively. Determine the radius of the larger sphere,if the diameter of the smaller one is $5 \, cm$. (in $cm$)

$1\, m^{3} = \dots \, cm^{3}$

Vedclass Test Series

Exam Paper Generator

Online Exam Module