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(D) The modulation index $m$ is given by the ratio of the peak voltage of the modulating signal $V_m$ to the peak voltage of the carrier wave $V_c$.$m

Vedclass · Accepted Answer

Modulation index $= 0.2$,side frequency bands are at $1220 \, kHz$ and $1180 \, kHz$

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(D) The modulation index $m$ is given by the ratio of the peak voltage of the modulating signal $V_m$ to the peak voltage of the carrier wave $V_c$.$m = \frac{V_m}{V_c} = \frac{5 \, V}{25 \, V} = 0.2$.Given,the frequency of the carrier wave $f_c = 1.2 \, MHz = 1200 \, kHz$.The frequency of the modulating signal $f_m = 20 \, kHz$.The sideband frequencies are given by $f_c \pm f_m$.Lower sideband frequency $= f_c - f_m = 1200 \, kHz - 20 \, kHz = 1180 \, kHz$.Upper sideband frequency $= f_c + f_m = 1200 \, kHz + 20 \, kHz = 1220 \, kHz$.Thus,the modulation index is $0.2$ and the sidebands are at $1180 \, kHz$ and $1220 \, kHz$.

$A$ signal of frequency $20 \, kHz$ and peak voltage $5 \, V$ is used to modulate a carrier wave of frequency $1.2 \, MHz$ and peak voltage $25 \, V$. Choose the correct statement.

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