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(C) The energy of the incident photon is given by $E = \frac{hc}{\lambda}$.Using $hc \approx 1240 \ eV \cdot nm$,we have $E = \frac{1240 \ eV \cdot nm

Vedclass · Accepted Answer

$1.5$

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(C) The energy of the incident photon is given by $E = \frac{hc}{\lambda}$.Using $hc \approx 1240 \ eV \cdot nm$,we have $E = \frac{1240 \ eV \cdot nm}{200 \ nm} = 6.2 \ eV$.The maximum kinetic energy $(K_{\max})$ of the emitted photoelectrons is given by Einstein's photoelectric equation: $K_{\max} = E - \phi$,where $\phi$ is the work function.$K_{\max} = 6.2 \ eV - 4.7 \ eV = 1.5 \ eV$.The maximum potential $(V_{\max})$ acquired by the ball is equal to the stopping potential,which is $V_{\max} = \frac{K_{\max}}{e} = 1.5 \ V$.

$A$ silver ball is suspended by a string in a vacuum chamber and ultraviolet light of wavelength $200 \ nm$ is incident on it. The maximum potential acquired by the ball,if the work function of silver is $4.7 \ eV$,will be .............. $V$.

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