A source of sound emitting a note of frequenc | vedclass

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(D) The Doppler effect formula for apparent frequency $f'$ is given by $f' = f \left( \frac{v_s \pm v_o}{v_s \mp v_s} \right)$,where $v_s$ is the velo

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$200$

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(D) The Doppler effect formula for apparent frequency $f'$ is given by $f' = f \left( \frac{v_s \pm v_o}{v_s \mp v_s} \right)$,where $v_s$ is the velocity of sound,$v_o$ is the velocity of the observer,and $v_s$ is the velocity of the source.Given that the source moves towards the observer with velocity $v = v_s$ and the observer moves away from the source with velocity $v = v_s$.Using the sign convention: $f' = f \left( \frac{v_s - v}{v_s - v} \right)$.Since $v = v_s$,the expression becomes $f' = f \left( \frac{v_s - v_s}{v_s - v_s} \right)$.However,in the case where both source and observer move with the same velocity in the same direction,there is no relative motion between them.Therefore,the relative velocity is zero,and the apparent frequency heard by the observer remains equal to the original frequency.Thus,$f' = 200 Hz$.

$A$ source of sound emitting a note of frequency $200 Hz$ moves towards an observer with a velocity $v$ equal to the velocity of sound. If the observer also moves away from the source with the same velocity $v$,the apparent frequency heard by the observer is .... $Hz$

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