A sphere is suspended by a thread of length l | vedclass

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(D) According to the law of conservation of mechanical energy,the kinetic energy given to the sphere at the lowest point must be equal to the potentia

Vedclass · Accepted Answer

$\sqrt{2gl}$

Vedclass · Answer

(D) According to the law of conservation of mechanical energy,the kinetic energy given to the sphere at the lowest point must be equal to the potential energy gained at the height of the suspension point.Let $m$ be the mass of the sphere and $v$ be the initial horizontal velocity.At the lowest point,the kinetic energy is $K.E. = \frac{1}{2}mv^2$.At the height of the suspension point,the potential energy is $P.E. = mgl$.Equating the two:$\frac{1}{2}mv^2 = mgl$Solving for $v$:$v^2 = 2gl$$v = \sqrt{2gl}$

$A$ sphere is suspended by a thread of length $l$. What minimum horizontal velocity has to be imparted to the ball for it to reach the height of the suspension point?

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