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(D) Given: $R_{steel} = 2R_{Al}$.Case $1$: When connected in series,the current $I$ flowing through both wires is the same. The heat dissipated is giv

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Both $(a)$ and $(b)$

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(D) Given: $R_{steel} = 2R_{Al}$.Case $1$: When connected in series,the current $I$ flowing through both wires is the same. The heat dissipated is given by $H = I^2Rt$. Since $I$ and $t$ are constant,$H \propto R$. Because $R_{steel} > R_{Al}$,more heat is dissipated in the steel wire.Case $2$: When connected in parallel,the voltage $V$ across both wires is the same. The heat dissipated is given by $H = \frac{V^2}{R}t$. Since $V$ and $t$ are constant,$H \propto \frac{1}{R}$. Because $R_{Al} Therefore,both statements $(a)$ and $(b)$ are correct.

$A$ steel wire has a resistance twice that of an aluminium wire. Both of them are connected to a constant voltage supply. More heat will be dissipated in:

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