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(C) When the stone is released from the moving train,it possesses an initial horizontal velocity equal to the velocity of the train.After release,ther

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Parabolic path

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(C) When the stone is released from the moving train,it possesses an initial horizontal velocity equal to the velocity of the train.After release,there is no horizontal force acting on the stone (ignoring air resistance),so its horizontal velocity remains constant.Simultaneously,the stone is subjected to a constant vertical downward acceleration due to gravity $(g)$.The combination of constant horizontal velocity and constant vertical acceleration results in a trajectory that is a parabola.Therefore,the stone will hit the ground following a parabolic path.

$A$ stone is just released from the window of a train moving along a horizontal straight track. The stone will hit the ground following:

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