$A$ straight line passes through $P(1, 2)$ such that its intercept between the axes is bisected at $P$. Its equation is:

$PS$ is the median of the triangle with vertices at $P(2, 2)$,$Q(6, -1)$,and $R(7, 3)$. The intercepts on the coordinate axes of the line passing through point $(1, -1)$ and parallel to $PS$ are respectively:

The equation $r \cos \left(\theta-\frac{\pi}{3}\right)=2$ represents

If the line $px - qy = r$ intersects the coordinate axes at $(a, 0)$ and $(0, b)$,then the value of $(a + b)$ is equal to

$A$ line cuts off equal intercepts on the coordinate axes. The angle made by this line with the positive direction of the $X$-axis is: (in $^{\circ}$)

If a line $L$ passes through the point of intersection of the lines $2x + 3y + 1 = 0$ and $x + y - 3 = 0$ and the angle made by the line $L$ with the $X$-axis measured in the positive direction from the positive $X$-axis is $\tan^{-1} \frac{2}{3}$,then the sum of the intercepts made by this line on the axes is