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Question

(C) The focal length of a lens is given by the Lens Maker's Formula: $\frac{1}{f} = (\mu_{lens} - 1) (\frac{1}{R_1} - \frac{1}{R_2})$.In air,the lens

Vedclass · Accepted Answer

Greater than air but less than water

Vedclass · Answer

(C) The focal length of a lens is given by the Lens Maker's Formula: $\frac{1}{f} = (\mu_{lens} - 1) (\frac{1}{R_1} - \frac{1}{R_2})$.In air,the lens acts as a convex lens,so $f > 0$,which implies $\mu_{lens} > 1$ (since $\mu_{air} = 1$).In water,the lens acts as a concave lens,so $f For the sign of $f$ to change,the term $(\frac{\mu_{lens}}{\mu_{water}} - 1)$ must be negative.This implies $\frac{\mu_{lens}}{\mu_{water}} Since $\mu_{air} < \mu_{lens} < \mu_{water}$,the refractive index of the substance is greater than air but less than water.

$A$ substance is behaving as a convex lens in air and a concave lens in water. What is its refractive index?

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