A swimmer can swim with speed 'v' with respec | vedclass

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(A) Let the velocity of the river be $\vec{u}$ and the velocity of the swimmer with respect to the water be $\vec{v}$.In the frame of reference of the

Vedclass · Accepted Answer

$\frac{2l}{v}$

Vedclass · Answer

(A) Let the velocity of the river be $\vec{u}$ and the velocity of the swimmer with respect to the water be $\vec{v}$.In the frame of reference of the river,the float is at rest.The swimmer moves away from the float with a speed '$v$' relative to the water (and thus relative to the float) for a distance '$l$'.The time taken to move away is $t_1 = \frac{l}{v}$.Then,the swimmer turns back and moves towards the float with a speed '$v$' relative to the water (and thus relative to the float) for the same distance '$l$'.The time taken to return is $t_2 = \frac{l}{v}$.The total time taken by the swimmer in this process is $T = t_1 + t_2 = \frac{l}{v} + \frac{l}{v} = \frac{2l}{v}$.

$A$ swimmer can swim with speed '$v$' with respect to still water in a river which is flowing with speed '$u$'. There is a float moving with the river. Now the swimmer overtakes the float,gets a lead of '$l$',and returns back to the float. The time taken by the swimmer in this process will be:

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