A thermocouple is formed by two metals X and | vedclass

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(D) In a thermocouple,the thermoelectric $EMF$ $(E)$ is given by $E = \alpha 	heta + \frac{1}{2} \beta 	heta^2$,where $	heta$ is the temperature di

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Both $(b)$ and $(c)$

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(D) In a thermocouple,the thermoelectric $EMF$ $(E)$ is given by $E = \alpha 	heta + \frac{1}{2} \beta 	heta^2$,where $	heta$ is the temperature difference between the junctions.Under normal conditions (temperature below the inversion temperature),the current flows from metal $X$ to metal $Y$ through the cold junction.When the temperature of the hot junction exceeds the temperature of inversion,the direction of the thermoelectric $EMF$ reverses.Consequently,the current direction reverses,flowing from $X$ to $Y$ through the hot junction,which is equivalent to flowing from $Y$ to $X$ through the cold junction.Therefore,both options $(b)$ and $(c)$ describe the same physical state.

$A$ thermocouple is formed by two metals $X$ and $Y$. Metal $X$ comes earlier than $Y$ in the Seebeck series. If the temperature of the hot junction increases beyond the temperature of inversion,then the direction of the current in the thermocouple will be:

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