A train has a speed of 60, km/h for the first | vedclass

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(B) The distance travelled by the train in the first $1\, h$ is $d_1 = 60\, km/h 	imes 1\, h = 60\, km$.The distance travelled by the train in the ne

Vedclass · Accepted Answer

$53.33$

Vedclass · Answer

(B) The distance travelled by the train in the first $1\, h$ is $d_1 = 60\, km/h 	imes 1\, h = 60\, km$.The distance travelled by the train in the next $0.5\, h$ is $d_2 = 40\, km/h 	imes 0.5\, h = 20\, km$.The total distance travelled is $D = d_1 + d_2 = 60\, km + 20\, km = 80\, km$.The total time taken is $T = 1\, h + 0.5\, h = 1.5\, h = 3/2\, h$.The average speed is given by $	ext{Average Speed} = \frac{	ext{Total Distance}}{	ext{Total Time}} = \frac{80}{1.5} = \frac{80}{3/2} = \frac{160}{3} \approx 53.33\, km/h$.

$A$ train has a speed of $60\, km/h$ for the first one hour and $40\, km/h$ for the next half hour. Its average speed in $km/h$ is

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