The displacement $(x)$ and time $(t)$ graph of a particle moving along a straight line is shown in the figure. The average velocity of the particle in the time of $10 \ s$ is (in $m \ s^{-1}$)

$A$ car covers a distance at a speed of $60 \ km \ h^{-1}$. It returns and comes back to the original point moving at a speed of $V$. If the average speed for the round trip is $48 \ km \ h^{-1}$,then the magnitude of $V$ is (in $km \ h^{-1}$)

Which among average speed and average velocity can be positive,negative or zero?

$A$ boy walks to his school at a distance of $6\, km$ with a constant speed of $2.5\, km/h$ and walks back with a constant speed of $4\, km/h$. His average speed for the round trip,expressed in $km/h$,is:

$A$ person walks along a straight road from his house to a market $2.5 \,km$ away with a speed of $5 \,km/h$ and instantly turns back and reaches his house with a speed of $7.5 \,km/h$. The average speed of the person during the time interval $0$ to $50 \,min$ is (in $m/s$)

$A$ man walks on a straight road from his home to a market $2.5 \; km$ away with a speed of $5 \; km \; h^{-1}$. Finding the market closed,he instantly turns and walks back home with a speed of $7.5 \; km \; h^{-1}$. What is the magnitude of average velocity in $m/s$?