A train running at a speed of 40 , m/s crosse | vedclass

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(C) Let the length of the train be $x \, m$.Then,the length of the bridge is $3.5x \, m$.Time taken to cross the pole $= \frac{	ext{Length of train}}

Vedclass · Accepted Answer

$840$

Vedclass · Answer

(C) Let the length of the train be $x \, m$.Then,the length of the bridge is $3.5x \, m$.Time taken to cross the pole $= \frac{	ext{Length of train}}{	ext{Speed}} = \frac{x}{40} \, s$.Time taken to cross the bridge $= \frac{	ext{Length of train} + 	ext{Length of bridge}}{	ext{Speed}} = \frac{x + 3.5x}{40} = \frac{4.5x}{40} \, s$.According to the problem,the difference in time is $21 \, s$:$\frac{4.5x}{40} - \frac{x}{40} = 21$$\frac{3.5x}{40} = 21$$3.5x = 21 	imes 40 = 840$$x = \frac{840}{3.5} = 240 \, m$.Length of the bridge $= 3.5x = 3.5 	imes 240 = 840 \, m$.

$A$ train running at a speed of $40 \, m/s$ crosses a pole in $21 \, s$ less than the time it requires to cross a bridge $3.5$ times its length at the same speed. What is the length of the bridge (in $m$)?

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