$A$ uniform cable of mass $M$ and length $L$ is placed on a horizontal surface such that its $(1/n)^{th}$ part is hanging below the edge of the surface. To lift the hanging part of the cable up to the surface,the work done should be
- A$nMgL$
- B$\frac{MgL}{2n^2}$
- C$\frac{2MgL}{n^2}$
- D$\frac{MgL}{n^2}$
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