A varying current at the rate of 3 , A/s in a | vedclass

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(A) The induced $e.m.f.$ $(e)$ in a coil due to a changing current in a nearby coil is given by the formula: $e = M \frac{di}{dt}$.Given:Rate of chang

Vedclass · Accepted Answer

$2.66 \, mH$

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(A) The induced $e.m.f.$ $(e)$ in a coil due to a changing current in a nearby coil is given by the formula: $e = M \frac{di}{dt}$.Given:Rate of change of current,$\frac{di}{dt} = 3 \, A/s$.Induced $e.m.f.$,$e = 8 \, mV = 8 	imes 10^{-3} \, V$.Substituting the values into the formula:$8 	imes 10^{-3} = M 	imes 3$.Solving for $M$:$M = \frac{8 	imes 10^{-3}}{3} \, H$.$M = 2.666... 	imes 10^{-3} \, H$.Since $10^{-3} \, H = 1 \, mH$,we get:$M = 2.66 \, mH$.

$A$ varying current at the rate of $3 \, A/s$ in a coil generates an $e.m.f.$ of $8 \, mV$ in a nearby coil. The mutual inductance of the two coils is:

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