A wave equation is given by y = 10^{-4} sin(6 | vedclass

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(C) The standard wave equation is $y = A \sin(\omega t + kx)$.Comparing the given equation $y = 10^{-4} \sin(60t + 2x)$ with the standard form:Angular

Vedclass · Accepted Answer

Wavelength of the wave is $\pi \ m$

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(C) The standard wave equation is $y = A \sin(\omega t + kx)$.Comparing the given equation $y = 10^{-4} \sin(60t + 2x)$ with the standard form:Angular frequency $\omega = 60 \ rad/s$ and wave number $k = 2 \ m^{-1}$.Since $\omega = 2\pi f$,we have $60 = 2\pi f$,which gives $f = \frac{30}{\pi} \ Hz$.Wave velocity $v = \frac{\omega}{k} = \frac{60}{2} = 30 \ m/s$. Since the sign between $\omega t$ and $kx$ is positive,the wave travels in the negative $x$-direction.Wavelength $\lambda = \frac{2\pi}{k} = \frac{2\pi}{2} = \pi \ m$.Comparing these results with the options,option $C$ is correct.

$A$ wave equation is given by $y = 10^{-4} \sin(60t + 2x)$,where $x$ and $y$ are in $meters$ and $t$ is in $seconds$. Which of the following statements is correct?

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