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(D) The circumference of the circle is $L = 2 \pi r = 2 \pi 	imes 0.1 \, m = 0.2 \pi \, m$.The total resistance of the wire is $R_{total} = (12 \, \O

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$0.6 \pi \, \Omega$

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(D) The circumference of the circle is $L = 2 \pi r = 2 \pi 	imes 0.1 \, m = 0.2 \pi \, m$.The total resistance of the wire is $R_{total} = (12 \, \Omega/m) 	imes (0.2 \pi \, m) = 2.4 \pi \, \Omega$.When the wire is bent into a circle and points $A$ and $B$ are diametrically opposite, the wire is divided into two equal semicircular parts, each with resistance $R' = R_{total} / 2 = 1.2 \pi \, \Omega$.These two parts are connected in parallel between points $A$ and $B$.The equivalent resistance $R_{eq}$ is given by $\frac{1}{R_{eq}} = \frac{1}{R'} + \frac{1}{R'} = \frac{2}{R'}$.Therefore, $R_{eq} = \frac{R'}{2} = \frac{1.2 \pi \, \Omega}{2} = 0.6 \pi \, \Omega$.

$A$ wire of resistance $12 \, \Omega/m$ is bent to form a complete circle of radius $10 \, cm$. The resistance between its two diametrically opposite points, $A$ and $B$, as shown in the figure, is:

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