A woman carrying two genes for haemophilia an | vedclass

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(C) Let the $X$ chromosome carrying the genes for haemophilia and colour blindness be denoted as $X^{hc}$. The normal $X$ chromosome is $X$. The woman

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$50\%$ haemophilic colourblind sons and $50\%$ normal sons

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(C) Let the $X$ chromosome carrying the genes for haemophilia and colour blindness be denoted as $X^{hc}$. The normal $X$ chromosome is $X$. The woman's genotype is $X^{hc}X$. The normal man's genotype is $XY$.Cross: $X^{hc}X 	imes XY$Gametes: $(X^{hc}, X)$ and $(X, Y)$Progeny genotypes: $X^{hc}X$ (carrier daughter),$X^{hc}Y$ (haemophilic and colourblind son),$XX$ (normal daughter),$XY$ (normal son).Thus,$50\%$ of the sons will be haemophilic and colourblind,and $50\%$ of the sons will be normal.

$A$ woman carrying two genes for haemophilia and one gene for colour blindness on one of her $X$ chromosomes marries a normal man. What will be the phenotype of the progeny?

Similar Questions

Which one of the following is a hereditary trait?

This type of disease is transmitted from a carrier mother to some of her sons.

What is the cause of haemophilia?

What will be the inheritance pattern of color blindness in children born to parents with normal vision,where the mother is a carrier for the color blindness gene?

Select the correct statement regarding colour blindness.

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