Acceleration due to gravity g for a body of m | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The gravitational force $F$ acting on a body of mass $m$ at the surface of the Earth is given by Newton's law of gravitation: $F = \frac{G M m}{R^

Vedclass · Accepted Answer

$m^0$

Vedclass · Answer

(B) The gravitational force $F$ acting on a body of mass $m$ at the surface of the Earth is given by Newton's law of gravitation: $F = \frac{G M m}{R^2}$.According to Newton's second law,the force is also $F = m g$,where $g$ is the acceleration due to gravity.Equating the two expressions: $m g = \frac{G M m}{R^2}$.Canceling $m$ from both sides,we get $g = \frac{G M}{R^2}$.Since $G$ and $M$ are constants for the Earth,$g$ is independent of the mass of the body $m$ (which can be written as $m^0$).Thus,$g$ is proportional to $m^0$.

Acceleration due to gravity $g$ for a body of mass $m$ on the Earth's surface is proportional to (Radius of Earth $= R$,mass of Earth $= M$)

Similar Questions

$R$ and $r$ are the radii of the Earth and Moon respectively. $\rho_e$ and $\rho_m$ are the densities of the Earth and Moon respectively. The ratio of the accelerations due to gravity on the surfaces of the Earth and Moon is

The weight of a body of mass $m$ decreases by $1\%$ when it is taken to a height $h$ above the surface of the Earth. What is the percentage decrease in its weight when it is taken to a depth $h$ below the surface of the Earth?

The radius of the Earth is $6400 \,km$ and the acceleration due to gravity is $g=10 \,ms^{-2}$. For the weight of a body of mass $5 \,kg$ to be zero at the equator,the rotational angular velocity of the Earth must be (in $rad/s$):

The time period of a simple pendulum increases by a factor of $\sqrt{2}$ at a height $h$ from the surface of the Earth. Then the value of $h$ is:

If the mass of the Sun were ten times smaller and the universal gravitational constant were ten times larger in magnitude,which of the following is not correct?

Vedclass Test Series

Exam Paper Generator

Online Exam Module