Accomplish the following conversions:
$(i)$ Nitrobenzene to benzoic acid
$(ii)$ Benzene to $m-$bromophenol
$(iii)$ Benzoic acid to aniline
$(iv)$ Aniline to $2,4,6-$tribromofluorobenzene
$(v)$ Benzyl chloride to $2-$phenylethanamine
$(vi)$ Chlorobenzene to $p-$chloroaniline
$(vii)$ Aniline to $p-$bromoaniline
$(viii)$ Benzamide to toluene
$(ix)$ Aniline to benzyl alcohol.

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(N/A) $(i)$ Nitrobenzene $\xrightarrow{Sn/HCl}$ Aniline $\xrightarrow{NaNO_2/HCl, 0-5^{\circ}C}$ Benzenediazonium chloride $\xrightarrow{CuCN}$ Benzonitrile $\xrightarrow{H_3O^+}$ Benzoic acid.
$(ii)$ Benzene $\xrightarrow{HNO_3/H_2SO_4}$ Nitrobenzene $\xrightarrow{Br_2/FeBr_3}$ $m-$Bromonitrobenzene $\xrightarrow{Sn/HCl}$ $m-$Bromoaniline $\xrightarrow{NaNO_2/HCl, 0-5^{\circ}C}$ $m-$Bromobenzenediazonium chloride $\xrightarrow{H_2O, \Delta}$ $m-$Bromophenol.
$(iii)$ Benzoic acid $\xrightarrow{NH_3, \Delta}$ Benzamide $\xrightarrow{Br_2/KOH}$ Aniline.
$(iv)$ Aniline $\xrightarrow{Br_2/H_2O}$ $2,4,6-$Tribromoaniline $\xrightarrow{NaNO_2/HCl, 0-5^{\circ}C}$ $2,4,6-$Tribromobenzenediazonium chloride $\xrightarrow{HBF_4, \Delta}$ $2,4,6-$Tribromofluorobenzene.
$(v)$ Benzyl chloride $\xrightarrow{KCN}$ Phenylacetonitrile $\xrightarrow{LiAlH_4}$ $2-$Phenylethanamine.
$(vi)$ Chlorobenzene $\xrightarrow{HNO_3/H_2SO_4}$ $p-$Nitrochlorobenzene $\xrightarrow{Sn/HCl}$ $p-$Chloroaniline.
$(vii)$ Aniline $\xrightarrow{(CH_3CO)_2O/Pyridine}$ Acetanilide $\xrightarrow{Br_2/CH_3COOH}$ $p-$Bromoacetanilide $\xrightarrow{H_3O^+}$ $p-$Bromoaniline.
$(viii)$ Benzamide $\xrightarrow{LiAlH_4}$ Benzylamine $\xrightarrow{NaNO_2/HCl}$ Benzyl alcohol $\xrightarrow{PCl_5}$ Benzyl chloride $\xrightarrow{Mg/ether, then H_2O}$ Toluene.
$(ix)$ Aniline $\xrightarrow{NaNO_2/HCl, 0-5^{\circ}C}$ Benzenediazonium chloride $\xrightarrow{CuCN}$ Benzonitrile $\xrightarrow{LiAlH_4}$ Benzylamine $\xrightarrow{HNO_2}$ Benzyl alcohol.

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Similar Questions

Primary and secondary amines can be distinguished by $:-$

Arrange the following:
$(i)$ In decreasing order of the $pK_{b}$ values:
$C_{2}H_{5}NH_{2}, C_{6}H_{5}NHCH_{3}, (C_{2}H_{5})_{2}NH$ and $C_{6}H_{5}NH_{2}$
$(ii)$ In increasing order of basic strength:
$C_{6}H_{5}NH_{2}, C_{6}H_{5}N(CH_{3})_{2}, (C_{2}H_{5})_{2}NH$ and $CH_{3}NH_{2}$
$(iii)$ In increasing order of basic strength:
$(a)$ Aniline,$p-$nitroaniline and $p-$toluidine
$(b)$ $C_{6}H_{5}NH_{2}, C_{6}H_{5}NHCH_{3}, C_{6}H_{5}CH_{2}NH_{2}$
$(iv)$ In decreasing order of basic strength in gas phase:
$C_{2}H_{5}NH_{2}, (C_{2}H_{5})_{2}NH, (C_{2}H_{5})_{3}N$ and $NH_{3}$
$(v)$ In increasing order of boiling point:
$C_{2}H_{5}OH, (CH_{3})_{2}NH, C_{2}H_{5}NH_{2}$
$(vi)$ In increasing order of solubility in water:
$C_{6}H_{5}NH_{2}, (C_{2}H_{5})_{2}NH, C_{2}H_{5}NH_{2}$

An aromatic amine $(A)$ was treated with alcoholic potash and another compound $(Y)$ to form a foul-smelling gas with the formula $C_6H_5NC$. Compound $(Y)$ was formed by reacting a compound $(Z)$ with $Cl_2$ in the presence of slaked lime. The compound $(Z)$ is:

Consider the above sequence of reactions. The number of bromine atom$(s)$ in the final product $(P)$ will be:

Number of structural isomers of $C_4H_{11}N$.

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