According to Bohr's atomic theory :-A. Kineti | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) According to Bohr's theory :$A$. $KE = 13.6 \frac{Z^{2}}{n^{2}} \ eV/atom \Rightarrow KE \propto \frac{Z^{2}}{n^{2}}$ (Correct)$B$. Speed of $e^{-

Vedclass · Accepted Answer

$A$ and $D$ only

Vedclass · Answer

(D) According to Bohr's theory :$A$. $KE = 13.6 \frac{Z^{2}}{n^{2}} \ eV/atom \Rightarrow KE \propto \frac{Z^{2}}{n^{2}}$ (Correct)$B$. Speed of $e^{-} \propto \frac{Z}{n} \Rightarrow v 	imes n \propto Z$ (Incorrect)$C$. Frequency of revolution of $e^{-} = \frac{v}{2 \pi r}$. Since $v \propto \frac{Z}{n}$ and $r \propto \frac{n^{2}}{Z}$,then Frequency $\propto \frac{Z/n}{n^{2}/Z} = \frac{Z^{2}}{n^{3}}$ (Incorrect)$D$. $F = \frac{kZe^{2}}{r^{2}}$. Since $r \propto \frac{n^{2}}{Z}$,then $F \propto \frac{Z}{(n^{2}/Z)^{2}} = \frac{Z^{3}}{n^{4}}$ (Correct)Thus,statements $A$ and $D$ are correct.

Similar Questions

The energy of the second excited state of the $Li^{2+}$ ion is ............... $eV$.

The ratio of the radii of two Bohr orbits of a hydrogen atom is $4:1$. What are their designations?

The maximum wavelength of radiation that can ionise a sodium atom is $2414 \ \mathring{A}$. The ionisation energy of sodium per mole shall be

The work function for a metal is $4 \, eV$. To emit a photo electron of zero velocity from the surface of the metal,the wavelength of incident light should be : ................ $\mathring{A}$

The radius of the second Bohr orbit,in terms of the Bohr radius,$a_{0}$,in $Li^{2+}$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module