Acidic dehydration of alcohol involves

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(D) Acidic dehydration of alcohols typically proceeds via the $E_1$ mechanism. $1$. The hydroxyl group is protonated to form a good leaving group $(-O

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(D) Acidic dehydration of alcohols typically proceeds via the $E_1$ mechanism. $1$. The hydroxyl group is protonated to form a good leaving group $(-OH_2^+)$. $2$. The leaving group departs to form a carbocation intermediate. $3$. If the carbocation can rearrange to a more stable form (e.g.,from secondary to tertiary),it will do so. $4$. Finally,a proton is removed to form an alkene,where the most substituted alkene (Saytzeff's product) is generally the major product due to its higher stability. Therefore,all the given statements are correct.

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