Iodoform is formed on warming $I_2$ and $NaOH$ with:

The $-OH$ group of methyl alcohol cannot be replaced by chlorine by the action of

Find the missing reagents $(x)$ and $(y)$ for the following reaction sequence:

Select the best method for the preparation of the following compounds:
(Image shows a mixture of trans$-2-$methylcyclohexanol enantiomers)
($MCPBA$ = meta-chloroperoxybenzoic acid)

In the reaction sequence $CH_2=CH_2$ $\xrightarrow{HOCl} X$ $\xrightarrow{Y} CH_2(OH)-CH_2(OH)$,$X$ and $Y$ respectively are:

$Ph-C(OH)(Ph)-C(OH)(CH_3)_2$ $(A)$ $+$ $Ph-C(OH)(Ph)-C(OH)(Et)_2$ $(B)$ $\xrightarrow{H_2SO_4}$
$(p)$ $Ph-C(Ph)(CH_3)-CO-CH_3$
$(q)$ $Ph-C(Ph)(Et)-CO-Et$
$(r)$ $Ph-C(Ph)(Et)-CO-CH_3$
$(s)$ $Ph-C(Ph)(CH_3)-CO-Et$
When $(A)$ and $(B)$ react with $H_2SO_4$,the products obtained are: