Select the best method for the preparation of | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The target compounds are a pair of enantiomers of $trans-2-methylcyclohexanol$.Step $1$: Reaction of cyclohexene with $MCPBA$ (meta-chloroperoxybe

Vedclass · Accepted Answer

reaction of cyclohexene with $MCPBA$,followed by $CH_3MgBr$

Vedclass · Answer

(D) The target compounds are a pair of enantiomers of $trans-2-methylcyclohexanol$.Step $1$: Reaction of cyclohexene with $MCPBA$ (meta-chloroperoxybenzoic acid) yields cyclohexene oxide (epoxide).Step $2$: The nucleophilic ring-opening of the epoxide with a Grignard reagent like $CH_3MgBr$ occurs via an $S_N2$ mechanism,leading to the trans-addition of the methyl group and the hydroxyl group.Therefore,the reaction of cyclohexene with $MCPBA$ followed by $CH_3MgBr$ is the correct method.

Select the best method for the preparation of the following compounds:
(Image shows a mixture of trans$-2-$methylcyclohexanol enantiomers)
($MCPBA$ = meta-chloroperoxybenzoic acid)

Similar Questions

Which among the following compounds has the lowest boiling point?

An alcohol having molecular weight $74$ gives white turbidity with Lucas reagent within $5-10$ minutes. It reacts with sodium metal to give $Y$. $Y$ reacts with $CH_3-Br$ to give $Z$. $Z$ is:

Ethylene glycol reacts with excess of $PCl_5$ to give

An unknown alcohol is treated with the "Lucas reagent" to determine whether the alcohol is primary,secondary,or tertiary. Which alcohol reacts fastest and by what mechanism?

Identify the structure of the product formed in the following reaction of $4-$chloro$-4-$methylpentan$-1-$ol in a neutral polar medium:
$(CH_3)_2C(Cl)CH_2CH_2CH_2OH \to HCl + C_6H_{12}O$

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Select the best method for the preparation of the following compounds:(Image shows a mixture of trans$-2-$methylcyclohexanol enantiomers)($MCPBA$ = meta-chloroperoxybenzoic acid)