Which among the following compounds has the l | vedclass

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(D) The boiling point of alcohols depends on the extent of intermolecular hydrogen bonding and the surface area of the molecule. For isomeric alcohols

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tert-Butanol ($2$-methylpropan-$2$-ol)

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(D) The boiling point of alcohols depends on the extent of intermolecular hydrogen bonding and the surface area of the molecule. For isomeric alcohols,the boiling point decreases as the degree of branching increases because branching reduces the surface area,which in turn decreases the magnitude of van der Waals forces. Comparing the given structures: $A$: $n$-Butanol (primary alcohol,straight chain) $B$: Isobutanol (primary alcohol,branched) $C$: sec-Butanol (secondary alcohol,branched) $D$: tert-Butanol (tertiary alcohol,highly branched) Among these isomers,tert-Butanol has the most branching,which results in the smallest surface area and the weakest van der Waals forces. Therefore,it has the lowest boiling point.

Which among the following compounds has the lowest boiling point?

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