All $Zn(II)$ compounds are white because
- A$Zn^{2+}$ has a $d^{10}$ configuration and the $d$-subshell is full
- B$Zn^{2+}$ shows $d-d$ transition
- C$Zn^{2+}$ has no electron in the $4s$-subshell
- D$Zn$ is not a transition element
Explore More
Similar Questions
Approximately what percentage $(\%)$ of the total elements are transition elements?
Medium
View SolutionAmong the following pairs of ions,the lower oxidation state in aqueous solution is more stable than the other in:
MediumAIIMS 2005
View SolutionWhich one of the following ions is the most stable in aqueous solution?
(At. No. $Ti = 22, V = 23, Cr = 24, Mn = 25$)
(At. No. $Ti = 22, V = 23, Cr = 24, Mn = 25$)
MediumAIPMT 2007
View SolutionThe atomic radii from $Cr$ to $Cu$ are almost identical because of:
Easy
View SolutionWhich of the following oxides has the maximum basicity?
Vedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo