All wires have the same resistance r. The equ | vedclass

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(B) Let the resistance of each wire be $r$. Initially,with keys $K_1$ and $K_2$ open,the circuit consists of $7$ resistors of resistance $r$ arranged

Vedclass · Accepted Answer

$\frac{7R}{9}$

Vedclass · Answer

(B) Let the resistance of each wire be $r$. Initially,with keys $K_1$ and $K_2$ open,the circuit consists of $7$ resistors of resistance $r$ arranged in a specific network. The equivalent resistance is given as $R$. When keys $K_1$ and $K_2$ are closed,they short-circuit the resistors connected in parallel to them. Specifically,the resistor in parallel with $K_1$ and the resistor in parallel with $K_2$ are bypassed,effectively removing them from the circuit. This leaves a simplified network of $5$ resistors,each of resistance $r$. By analyzing the circuit,the new equivalent resistance $R_{eq}$ becomes $\frac{7R}{9}$.

All wires have the same resistance $r$. The equivalent resistance between $A$ and $B$ is $R$. Now,if the keys $K_1$ and $K_2$ are closed,what will be the new equivalent resistance?

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