Among the following $Cr(III)$ complexes,which one will have the highest octahedral crystal field splitting?

Draw a figure to show the splitting of $d$ orbitals in an octahedral crystal field.

Match the $LIST$-$I$ with $LIST$-$II$:

List-$I$ (Electronic configuration of tetrahedral metal ion)	List-$II$ (Crystal Field Stabilization Energy $(\Delta_t)$)
$A$. $d^2$	$I$. $-0.6$
$B$. $d^4$	$II$. $-0.8$
$C$. $d^6$	$III$. $-1.2$
$D$. $d^8$	$IV$. $-0.4$

If $[Cu(H_{2}O)_{4}]^{2+}$ absorbs light of wavelength $600 \ nm$ for $d-d$ transition,then the value of octahedral crystal field splitting energy for $[Cu(H_{2}O)_{6}]^{2+}$ will be $..... \times 10^{-21} \ J$. (Nearest Integer)
(Given: $h = 6.63 \times 10^{-34} \ Js$ and $c = 3.08 \times 10^{8} \ ms^{-1}$)

Which of the following represents the correct increasing order of crystal field splitting energy?

The crystal field stabilization energy for a high spin $d^4$ octahedral complex is: