Among the following series of transition meta | vedclass

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(B) The correct option is $(B)$.To determine the electronic configuration,we look at the atomic numbers of the elements:$Ti (Z=22): [Ar] 3d^2 4s^2 \im

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$Ti^{2+}, V^{3+}, Cr^{4+}, Mn^{5+}$

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(B) The correct option is $(B)$.To determine the electronic configuration,we look at the atomic numbers of the elements:$Ti (Z=22): [Ar] 3d^2 4s^2 \implies Ti^{2+} = [Ar] 3d^2$$V (Z=23): [Ar] 3d^3 4s^2 \implies V^{3+} = [Ar] 3d^2$$Cr (Z=24): [Ar] 3d^5 4s^1 \implies Cr^{4+} = [Ar] 3d^2$$Mn (Z=25): [Ar] 3d^5 4s^2 \implies Mn^{5+} = [Ar] 3d^2$Thus,all ions in option $(B)$ have a $3d^2$ configuration.

Among the following series of transition metal ions,the one where all metal ions have $3d^2$ electronic configuration is

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