Amongst FeCl_{3} cdot 3H_{2}O,K_{3}[Fe(CN)_{6 | vedclass

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(C) The inner-orbital complexes are $K_{3}[Fe(CN)_{6}]$ and $[Co(NH_{3})_{6}]Cl_{3}$.$K_{3}[Fe(CN)_{6}]$ contains $Fe^{3+}$ $(3d^{5})$,which forms a $

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$2$

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(C) The inner-orbital complexes are $K_{3}[Fe(CN)_{6}]$ and $[Co(NH_{3})_{6}]Cl_{3}$.$K_{3}[Fe(CN)_{6}]$ contains $Fe^{3+}$ $(3d^{5})$,which forms a $d^{2}sp^{3}$ complex with $1$ unpaired electron. Its spin-only magnetic moment is $\mu = \sqrt{1(1+2)} = \sqrt{3} \approx 1.732 \ B.M.$$[Co(NH_{3})_{6}]Cl_{3}$ contains $Co^{3+}$ $(3d^{6})$,which forms a $d^{2}sp^{3}$ complex with $0$ unpaired electrons. Its spin-only magnetic moment is $\mu = 0 \ B.M.$$CN^{-}$ is a stronger field ligand than $NH_{3}$,so $K_{3}[Fe(CN)_{6}]$ has a larger crystal field splitting energy $(\Delta_{0})$ than $[Co(NH_{3})_{6}]Cl_{3}$.Since $\Delta_{0} = \frac{hc}{\lambda}$,a larger $\Delta_{0}$ corresponds to a shorter wavelength $(\lambda)$ of absorbed light.Therefore,$K_{3}[Fe(CN)_{6}]$ is the complex that absorbs light at the shortest wavelength.Its spin-only magnetic moment is $1.732 \ B.M.$,which rounds to $2$ to the nearest integer.

List-$I$	List-$II$
$A$. $[Fe(H_2O)_6]^{2+}$	$P$. $0$
$B$. $[Fe(H_2O)_6]^{3+}$	$Q$. $1$
$C$. $[Fe(CN)_6]^{4-}$	$R$. $2$
$D$. $[Fe(CN)_6]^{3-}$	$S$. $4$
$E$. $[Ni(H_2O)_4]^{2+}$	$T$. $5$

Amongst $FeCl_{3} \cdot 3H_{2}O$,$K_{3}[Fe(CN)_{6}]$ and $[Co(NH_{3})_{6}]Cl_{3}$,the spin-only magnetic moment value of the inner-orbital complex that absorbs light at the shortest wavelength is $B.M.$ [nearest integer].

Similar Questions

Which of the following complexes is optically inactive?

Which complex possesses a facial $(fac)$ isomer?

Match the complex ion (in List-$I$) with the number of unpaired electrons (in List-$II$):

List-$I$ List-$II$

$A$. $[Fe(H_2O)_6]^{2+}$ $P$. $0$

$B$. $[Fe(H_2O)_6]^{3+}$ $Q$. $1$

$C$. $[Fe(CN)_6]^{4-}$ $R$. $2$

$D$. $[Fe(CN)_6]^{3-}$ $S$. $4$

$E$. $[Ni(H_2O)_4]^{2+}$ $T$. $5$

The coordination number,oxidation number,number of electrons in $d$-orbital,and number of unpaired electrons respectively in the complex $[Co(NH_3)_4CO_3]ClO_4$ are . . . . . . .

Identify the ion (hydrated in solution) which is not correctly matched with its spin only magnetic moment (in $BM$) given in brackets.

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