Match the complex ion (in List-I) with the nu | vedclass

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(A) . $[Fe(H_2O)_6]^{2+}$: $Fe^{2+}$ is $d^6$. $H_2O$ is a weak field ligand. Configuration is $t_{2g}^4 e_g^2$. Unpaired electrons = $4$ $(S)$.$B$. $

Vedclass · Accepted Answer

$A-S, B-T, C-P, D-Q, E-R$

Vedclass · Answer

(A) . $[Fe(H_2O)_6]^{2+}$: $Fe^{2+}$ is $d^6$. $H_2O$ is a weak field ligand. Configuration is $t_{2g}^4 e_g^2$. Unpaired electrons = $4$ $(S)$.$B$. $[Fe(H_2O)_6]^{3+}$: $Fe^{3+}$ is $d^5$. $H_2O$ is a weak field ligand. Configuration is $t_{2g}^3 e_g^2$. Unpaired electrons = $5$ $(T)$.$C$. $[Fe(CN)_6]^{4-}$: $Fe^{2+}$ is $d^6$. $CN^-$ is a strong field ligand. Configuration is $t_{2g}^6 e_g^0$. Unpaired electrons = $0$ $(P)$.$D$. $[Fe(CN)_6]^{3-}$: $Fe^{3+}$ is $d^5$. $CN^-$ is a strong field ligand. Configuration is $t_{2g}^5 e_g^0$. Unpaired electrons = $1$ $(Q)$.$E$. $[Ni(H_2O)_4]^{2+}$: $Ni^{2+}$ is $d^8$. $H_2O$ is a weak field ligand. Configuration is $t_{2g}^6 e_g^2$. Unpaired electrons = $2$ $(R)$.Thus,the correct match is $A-S, B-T, C-P, D-Q, E-R$.

List-$I$	List-$II$
$A$. $[Fe(H_2O)_6]^{2+}$	$P$. $0$
$B$. $[Fe(H_2O)_6]^{3+}$	$Q$. $1$
$C$. $[Fe(CN)_6]^{4-}$	$R$. $2$
$D$. $[Fe(CN)_6]^{3-}$	$S$. $4$
$E$. $[Ni(H_2O)_4]^{2+}$	$T$. $5$

Match the complex ion (in List-$I$) with the number of unpaired electrons (in List-$II$):

List-$I$ List-$II$

$A$. $[Fe(H_2O)_6]^{2+}$ $P$. $0$

$B$. $[Fe(H_2O)_6]^{3+}$ $Q$. $1$

$C$. $[Fe(CN)_6]^{4-}$ $R$. $2$

$D$. $[Fe(CN)_6]^{3-}$ $S$. $4$

$E$. $[Ni(H_2O)_4]^{2+}$ $T$. $5$

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Match the complex ion (in List-$I$) with the number of unpaired electrons (in List-$II$): List-$I$ List-$II$ $A$. $[Fe(H_2O)_6]^{2+}$ $P$. $0$ $B$. $[Fe(H_2O)_6]^{3+}$ $Q$. $1$ $C$. $[Fe(CN)_6]^{4-}$ $R$. $2$ $D$. $[Fe(CN)_6]^{3-}$ $S$. $4$ $E$. $[Ni(H_2O)_4]^{2+}$ $T$. $5$