An $LED$ is manufactured using zinc selenide; then it emits:

  • A
    infrared radiation
  • B
    yellow light
  • C
    blue light
  • D
    green light

Explore More

Similar Questions

Explain why elemental semiconductors cannot be used to make visible $LEDs$.

Why is the $I-V$ characteristic of a solar cell drawn in the fourth quadrant of the coordinate system?

An $LED$ is a $p-n$ junction diode which is

If the energy gap of a semiconductor used for the fabrication of an $LED$ is nearly $1.9 \ eV$, then the color of the light emitted by the $LED$ is

$A$ $p-n$ photodiode is made of a material with a band gap of $2.0\, eV$. The minimum frequency of the radiation that can be absorbed by the material is nearly:

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo