An X-ray tube produces a continuous spectrum | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The energy of a photon is given by the formula $E = \frac{hc}{\lambda}$.Given, $\lambda = 45 	imes 10^{-2} 	ext{ Å} = 45 	imes 10^{-12} 	ext{

Vedclass · Accepted Answer

$27$

Vedclass · Answer

(A) The energy of a photon is given by the formula $E = \frac{hc}{\lambda}$.Given, $\lambda = 45 	imes 10^{-2} 	ext{ Å} = 45 	imes 10^{-12} 	ext{ m}$.Substituting the values: $E = \frac{6.62 	imes 10^{-34} 	imes 3 	imes 10^8}{45 	imes 10^{-12}} 	ext{ J}$.$E = \frac{19.86 	imes 10^{-26}}{45 	imes 10^{-12}} 	ext{ J} = 0.4413 	imes 10^{-14} 	ext{ J}$.To convert energy into $eV$, divide by the charge of an electron $(1.6 	imes 10^{-19} 	ext{ C})$:$E_{eV} = \frac{0.4413 	imes 10^{-14}}{1.6 	imes 10^{-19}} 	ext{ eV} \approx 0.2758 	imes 10^5 	ext{ eV} = 27,580 	ext{ eV}$.Rounding to the nearest given option, the value is $27,500 	ext{ eV}$.

An $X$-ray tube produces a continuous spectrum of radiation with its shortest wavelength of $45 \times 10^{-2} \text{ Å}$. The maximum energy of a photon in the radiation in $eV$ is (in $27,500$). $(h = 6.62 \times 10^{-34} \text{ J-s}, c = 3 \times 10^8 \text{ m/s})$.

Similar Questions

$X-$rays are produced due to

Consider a photon of continuous $X$-ray and a photon of characteristic $X$-ray of the same wavelength. Which of the following is different for the two photons?

The shortest wavelength of $X-$rays emitted from an $X-$ray tube depends upon

$X$-rays cannot be deflected by means of an ordinary grating due to

If the lattice constant of a crystal is $3 \times 10^{-8} \, cm$ and the glancing angle for the first-order diffraction of $X$-rays is $30^{\circ}$,then the value of $\lambda$ will be ..... $\times 10^{-8} \, cm$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module