An e.m.f. of 12 V is induced in a coil when t | vedclass

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(B) The formula for the induced $e.m.f.$ in a coil due to self-induction is given by $e = L \cdot \frac{di}{dt}$.Given:Induced $e.m.f.$ $(e)$ = $12$ $

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$15$

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(B) The formula for the induced $e.m.f.$ in a coil due to self-induction is given by $e = L \cdot \frac{di}{dt}$.Given:Induced $e.m.f.$ $(e)$ = $12$ $V$.Rate of change of current $(\frac{di}{dt})$ = $48$ $A/min$.First, convert the rate of change of current into $A/s$:$\frac{di}{dt} = \frac{48 	ext{ A}}{60 	ext{ s}} = 0.8 	ext{ A/s}$.Now, substitute the values into the formula:$L = \frac{e}{di/dt} = \frac{12}{0.8} = 15 	ext{ H}$.Therefore, the self-inductance of the coil is $15 	ext{ H}$.

An $e.m.f.$ of $12$ $V$ is induced in a coil when the current in it changes at the rate of $48$ $A/min$. The self-inductance of the coil is:

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