An X-ray has a wavelength of 0.010 mathring{A | vedclass

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(B) The momentum $p$ of a photon is given by the de Broglie relation: $p = \frac{h}{\lambda}$.Given:Planck's constant $h = 6.626 	imes 10^{-34} 	ext

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$6.626 	imes 10^{-22} 	ext{ kg m/s}$

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(B) The momentum $p$ of a photon is given by the de Broglie relation: $p = \frac{h}{\lambda}$.Given:Planck's constant $h = 6.626 	imes 10^{-34} 	ext{ J s}$.Wavelength $\lambda = 0.010 \mathring{A} = 0.010 	imes 10^{-10} 	ext{ m} = 10^{-12} 	ext{ m}$.Substituting the values:$p = \frac{6.626 	imes 10^{-34}}{10^{-12}} = 6.626 	imes 10^{-22} 	ext{ kg m/s}$.

An $X$-ray has a wavelength of $0.010 \mathring{A}$. Its momentum is

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