An air capacitor has a capacitance of 1 mu F. | vedclass

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(A) The capacitance of a parallel plate air capacitor is given by $C = \frac{\varepsilon_0 A}{d} = 1 \mu F$. From the figure,the area of each plate is

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$3$

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(A) The capacitance of a parallel plate air capacitor is given by $C = \frac{\varepsilon_0 A}{d} = 1 \mu F$. From the figure,the area of each plate is divided into two halves,$A/2$ and $A/2$,while the distance $d$ remains the same for both. This configuration represents two capacitors in parallel. For the first dielectric $(K_1 = 4)$: $C_1 = \frac{K_1 \varepsilon_0 (A/2)}{d} = K_1 	imes \frac{1}{2} 	imes C = 4 	imes 0.5 	imes 1 \mu F = 2 \mu F$. For the second dielectric $(K_2 = 2)$: $C_2 = \frac{K_2 \varepsilon_0 (A/2)}{d} = K_2 	imes \frac{1}{2} 	imes C = 2 	imes 0.5 	imes 1 \mu F = 1 \mu F$. Since the capacitors are in parallel,the effective capacitance is: $C_{	ext{eff}} = C_1 + C_2 = 2 \mu F + 1 \mu F = 3 \mu F$.

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