An alcohol on oxidation is found to give CH_3 | vedclass

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(D) The oxidation of a secondary alcohol under vigorous conditions leads to the cleavage of the $C-C$ bond adjacent to the carbonyl group formed after

Vedclass · Accepted Answer

$CH_3CH(OH)CH_2CH_2CH_3$

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(D) The oxidation of a secondary alcohol under vigorous conditions leads to the cleavage of the $C-C$ bond adjacent to the carbonyl group formed after initial oxidation to a ketone.The given products are acetic acid ($CH_3COOH$,$2$ carbons) and propanoic acid ($CH_3CH_2COOH$,$3$ carbons).This implies the original alcohol must have a total of $5$ carbon atoms with the hydroxyl group at the $C-2$ position.The structure $CH_3CH(OH)CH_2CH_2CH_3$ (pentan-$2$-ol) undergoes oxidation to break the bond between $C-2$ and $C-3$,resulting in $CH_3COOH$ and $CH_3CH_2COOH$.

An alcohol on oxidation is found to give $CH_3COOH$ and $CH_3CH_2COOH$. The structure of the alcohol is

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