An alloy made up of A and B metals crystallis | vedclass

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Question

(B) In a cubic lattice:$B$ atoms occupy the corners. The number of corners in a cube is $8$, and the contribution of each atom at the corner is $1/8$.

Vedclass · Accepted Answer

$A_3B$

Vedclass · Answer

(B) In a cubic lattice:$B$ atoms occupy the corners. The number of corners in a cube is $8$, and the contribution of each atom at the corner is $1/8$.Number of $B$ atoms $= 8 	imes (1/8) = 1$.$A$ atoms occupy the face centers. The number of faces in a cube is $6$, and the contribution of each atom at the face center is $1/2$.Number of $A$ atoms $= 6 	imes (1/2) = 3$.Therefore, the ratio of $A:B$ is $3:1$, and the formula of the alloy is $A_3B$.

An alloy made up of $A$ and $B$ metals crystallises in a cubic lattice, where $B$ atoms occupy the corners and $A$ atoms occupy the face centers. The formula of the alloy formed is

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