An alloy of copper and zinc is taken in the r | vedclass

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(C) Let the fraction of copper in the first alloy be $\frac{1}{3}$ and in the second alloy be $\frac{2}{5}$.The fraction of copper in the final alloy

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$3$ and $5$

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(C) Let the fraction of copper in the first alloy be $\frac{1}{3}$ and in the second alloy be $\frac{2}{5}$.The fraction of copper in the final alloy is $\frac{3}{8}$.Using the rule of alligation:Difference for the first alloy: $\frac{2}{5} - \frac{3}{8} = \frac{16-15}{40} = \frac{1}{40}$.Difference for the second alloy: $\frac{3}{8} - \frac{1}{3} = \frac{9-8}{24} = \frac{1}{24}$.The required ratio of the two alloys is $\frac{1}{40} : \frac{1}{24} = 24 : 40 = 3 : 5$.Thus,$3$ and $5$ parts of the two alloys must be taken.

An alloy of copper and zinc is taken in the ratio $1: 2$,and another alloy of the same metals is taken in the ratio of $2: 3$. How many parts of the two alloys must be taken to obtain a new alloy consisting of copper and zinc that are in the ratio $3: 5$?

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