An e.m.f. E=4 cos (1000 t) volt is applied to | vedclass

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(D) For an $LR$ circuit,the impedance $Z$ is given by $Z = \sqrt{R^2 + (\omega L)^2}$.Comparing the given equation $E = 4 \cos(1000 t)$ with the stand

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$0.8 \ A$

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(D) For an $LR$ circuit,the impedance $Z$ is given by $Z = \sqrt{R^2 + (\omega L)^2}$.Comparing the given equation $E = 4 \cos(1000 t)$ with the standard equation $E = E_0 \cos(\omega t)$,we get $E_0 = 4 \ V$ and $\omega = 1000 \ rad/s$.Given $L = 3 \ mH = 3 	imes 10^{-3} \ H$ and $R = 4 \ \Omega$.The inductive reactance is $X_L = \omega L = 1000 	imes 3 	imes 10^{-3} = 3 \ \Omega$.Now,calculate the impedance $Z = \sqrt{R^2 + X_L^2} = \sqrt{4^2 + 3^2} = \sqrt{16 + 9} = \sqrt{25} = 5 \ \Omega$.The maximum current $I_0$ is given by $I_0 = \frac{E_0}{Z} = \frac{4}{5} = 0.8 \ A$.

An e.m.f. $E=4 \cos (1000 t)$ volt is applied to an $LR$ circuit of inductance $3 \ mH$ and resistance $4 \ \Omega$. The maximum current in the circuit is

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