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(A) The behavior of amino acids in an electric field depends on their net charge at a given $pH$ relative to their isoelectric point $(pI)$.$1$. For g

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Glutamic acid migrates to the anode at $pH$ $6.0$. Arginine is present as a cation and migrates to the cathode. Alanine exists as a zwitterion and remains uniformly distributed in the solution.

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(A) The behavior of amino acids in an electric field depends on their net charge at a given $pH$ relative to their isoelectric point $(pI)$.$1$. For glutamic acid $(pI = 3.2)$, at $pH = 6.0$ $(pH > pI)$, it exists as an anion and migrates to the anode.$2$. For arginine $(pI = 10.7)$, at $pH = 6.0$ $(pH $3$. For alanine $(pI = 6.0)$, at $pH = 6.0$ $(pH = pI)$, it exists as a zwitterion (dipolar ion) with a net charge of zero and does not migrate to either electrode, remaining uniformly distributed.

An electric current is passed through an aqueous solution of a mixture of alanine (isoelectric point $6.0$), glutamic acid $(3.2)$, and arginine $(10.7)$ buffered at $pH$ $6.0$. What is the fate of the three amino acids?

Similar Questions

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