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Question

(C) Let the mass of liquid ammonia be $m$ and the rate of heat supplied by the heater be $r$.According to the principle of calorimetry, the heat suppl

Vedclass · Accepted Answer

$1127$

Vedclass · Answer

(C) Let the mass of liquid ammonia be $m$ and the rate of heat supplied by the heater be $r$.According to the principle of calorimetry, the heat supplied to raise the temperature is given by $Q_1 = r 	imes 14 = m 	imes c 	imes \Delta T$.Substituting the values: $r 	imes 14 = m 	imes 4.9 	imes (50 - 15)$.$r 	imes 14 = m 	imes 4.9 	imes 35$  --- (Equation $1$).The heat supplied to convert the liquid to vapour at the boiling point is $Q_2 = r 	imes 92 = m 	imes L$.$r 	imes 92 = m 	imes L$ --- (Equation $2$).Dividing Equation $2$ by Equation $1$:$\frac{r 	imes 92}{r 	imes 14} = \frac{m 	imes L}{m 	imes 4.9 	imes 35}$.$\frac{92}{14} = \frac{L}{4.9 	imes 35}$.$L = \frac{92 	imes 4.9 	imes 35}{14}$.$L = 92 	imes 4.9 	imes 2.5 = 1127 	ext{ kJ/kg}$.

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