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(D) When a charged particle enters a uniform magnetic field perpendicular to the field lines,the magnetic Lorentz force acts as a centripetal force.$F

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in a circular path with a radius directly proportional to its velocity

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(D) When a charged particle enters a uniform magnetic field perpendicular to the field lines,the magnetic Lorentz force acts as a centripetal force.$F = qvB = \frac{mv^2}{r}$From this,the radius $r$ of the circular path is given by:$r = \frac{mv}{qB}$Since $m$,$q$,and $B$ are constants,we have $r \propto v$.Therefore,the particle travels in a circular path with a radius directly proportional to its velocity.

An electrically charged particle enters a uniform magnetic field in a direction perpendicular to the field with a velocity $v$. Then,it travels

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