An electron,a doubly ionized helium ion $(He^{++})$ and a proton have the same kinetic energy. The relation between their respective de-Broglie wavelengths $\lambda_{e}, \lambda_{He^{++}}$ and $\lambda_{P}$ is:

• A
  $\lambda_{e} < \lambda_{P} < \lambda_{He^{++}}$
• B
  $\lambda_{e} < \lambda_{He^{++}} = \lambda_{P}$
• C
  $\lambda_{e} > \lambda_{He^{++}} > \lambda_{P}$
• D
  $\lambda_{e} > \lambda_{P} > \lambda_{He^{++}}$