An electron and a proton are separated by a l | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The initial energy of the system is the kinetic energy of the electron, $E_i = 3 \, eV$.The energy of the hydrogen atom in the $n^{th}$ state is g

Vedclass · Accepted Answer

$1.41$

Vedclass · Answer

(C) The initial energy of the system is the kinetic energy of the electron, $E_i = 3 \, eV$.The energy of the hydrogen atom in the $n^{th}$ state is given by $E_n = -\frac{13.6 \, eV}{n^2}$.The second excited state corresponds to $n = 3$. Thus, $E_f = -\frac{13.6 \, eV}{3^2} = -\frac{13.6}{9} \, eV \approx -1.51 \, eV$.The energy released as a photon is the difference between the initial and final energy: $E_{photon} = E_i - E_f = 3 \, eV - (-1.51 \, eV) = 4.51 \, eV$.The work function $\phi$ of the metal is $\phi = \frac{hc}{\lambda_{threshold}} = \frac{12400 \, eV \cdot Å}{4000 \, Å} = 3.1 \, eV$.Using Einstein's photoelectric equation, the maximum kinetic energy is $KE_{max} = E_{photon} - \phi = 4.51 \, eV - 3.1 \, eV = 1.41 \, eV$.

Similar Questions

If the threshold wavelength for sodium is $6800 \mathring{A}$,then the work function will be ............. $eV$.

For zero photoelectric current,the stopping potential is:

If the stopping potential of photoelectrons emitted by a source placed at a distance of $0.2 \ m$ from a photocell is $0.6 \ V$,then the stopping potential of photoelectrons emitted by the same source placed at a distance of $0.6 \ m$ from the photocell will be .......... $V$.

The work function of a metal is $2.51 eV$. Its threshold frequency is:

When a photon of energy $hv$ is incident on an aluminum plate with a work function $E_0$,the maximum kinetic energy of the emitted photoelectrons is $K$. If the frequency of the incident radiation is doubled,the maximum kinetic energy of the emitted photoelectrons will be .......

Vedclass Test Series

Exam Paper Generator

Online Exam Module